🔥🌟 MDCAT/ECAT/FSC Grand Chemistry MCQs Quiz # 8 (Advance Level) | Interactive Quiz 🧪💡| Learn & Practice!

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1: The value of solubility product depends only on

a) Solvent

b) Catalyst

c) Temperature

d) Pressure

✅ Correct Answer: (c) Temperature

🔎📌 Short Reason

Solubility product is an equilibrium constant, and equilibrium constants are functions of temperature only. Changes in solvent, catalyst, or pressure do not alter the intrinsic Kₛₚ value
🔎🧠 Step by Step Reasoning
🔎Kₛₚ is an equilibrium constant for the dissolution of a sparingly soluble salt.
🔎Like all equilibrium constants, its value depends only on temperature.
🔎It does not depend on solvent (though solubility itself can vary with solvent), catalyst (irrelevant here), or pressure (important for gases, but salts are solids).

2: The unit in which wave number is measured:

a) sec⁻¹

b) hertz

c) cm⁻¹

d) nanometer

✅ Correct Answer: (c) cm⁻¹

🔎📌 Short Reason

Wave number is the reciprocal of wavelength, so its unit is per centimeter (cm⁻¹).
🔎🧠 Step by Step Reasoning
Wave number (ν̅ = nu̅) is defined as the reciprocal of wavelength:
Since wavelength (λ) is usually expressed in centimeters, the unit of wave number becomes cm⁻¹
Other options:
sec⁻¹ → unit of frequency (not wave number)
hertz (Hz) → also frequency (s⁻¹)
nanometer → unit of wavelength, not wave number

3: A line in Pfund series is obtained when an electron from higher energy levels returns to

a) 1st orbit

b) 5th orbit

c) 3rd orbit

d) 6th orbit

✅ Correct Answer: (b) 5th orbit

🔎📌 Short Reason

The Pfund series is part of the hydrogen emission spectrum. It arises when electrons drop from higher energy levels (n ≥ 6) down to n = 5
🔎🧠 Step by Step Reasoning
Hydrogen spectral series are defined by the final orbit (n) to which the electron falls:
📌Lyman series → electron falls to n = 1
📌Balmer series → electron falls to n = 2
📌Paschen series → electron falls to n = 3
📌Brackett series → electron falls to n = 4
📌Pfund series → electron falls to n = 5
👉🏼So, Pfund series corresponds to transitions ending at the 5th orbit.

4: The energy of an electron in Bohr’s atom ……….. as we move away from the nucleus:

a) Increases

b) Decreases

c) Remains same

d) Unpredicted

✅ Correct Answer: (a) Increases

🔎📌 Short Reason

In Bohr’s atom, electron energy is negative and increases toward zero as the electron moves away from the nucleus. Hence, energy increases with distance.
🔎🧠 Step by Step Reasoning
📌 The energy of an electron in the nth Bohr’s orbit is given by: Eₙ = −13.6/n² eV
📌As n increases (electron moves farther from the nucleus):
📌The denominator n² increases.
📌The negative value becomes less negative (closer to zero).
📌This means the electron’s energy increases (approaches 0).
⚛️Physically:
📌Near the nucleus → electron is strongly bound → lower energy (more negative).
📌Farther away → electron is less bound → higher energy (less negative).

5: The energy of an electron in the first orbit in hydrogen atom is −313.6/n² kcalmol⁻¹. The energy of electron in 3rd orbit is given by:

a) −313.6/3 kcal mol⁻¹

b) −313.6/9 kcal mol⁻¹

c) −313.6/2 kcal mol⁻¹

d) −313.6 × 3 kcal mol⁻¹

✅ Correct Answer: (b) −313.6/9 kcal mol⁻¹
🔎📌 Short Reason
Energy in Bohr’s atom decreases in magnitude as n increases.
For n = 3, substitute into the formula → −313.6/9.
🔎🧠 Step by Step Reasoning
📌 Formula:
📌 For nth orbit: Eₙ = −313.6/n²
📌 For n = 3: E₃ = −313.6/3²
📌 Simplify: E₃ = −313.6/9 kcal mol⁻¹

6: The radius of the first orbit in hydrogen atom is 0.529 Å. The radius of the second orbit is:

a) ½ × 0.529 Å

b) 2 × 0.529 Å

c) 8 × 0.529 Å

d) 4 × 0.529 Å

✅ Correct Answer: (d) 4 × 0.529 Å
🔎📌 Short Reason
Bohr’s formula shows orbit radius increases with n².
For n = 2, radius = 4 × 0.529 Å = 2.116 Å.
🔎🧠 Step by Step Reasoning
📌 The radius of the nth Bohr’s orbit is: rₙ = n²⋅r₁ (where r₁ =0.529 Å).
📌 For n = 2: r₂ = 2²⋅r₁ = 4⋅r₁ = 4 ⋅ 0.529 Å= 2.116 Å
📌 Numerical value: r₂ = 2.116 A˚

7: Electromagnetic radiations with minimum wavelength are:

a) Ultraviolet

b) X rays

c) Infrared

d) Radiowave

✅ Correct Answer: (b) X rays
🔎📌 Short Reason
In the electromagnetic spectrum, X rays lie between ultraviolet and gamma rays. They have much shorter wavelength than UV, IR, or radiowaves, so they represent the minimum wavelength among the given choices.
🔎🧠 Step by Step Reasoning
🔎Electromagnetic spectrum order (increasing wavelength):
Gamma rays < X rays < Ultraviolet < Visible < Infrared < Microwaves < Radiowaves
📌 Minimum wavelength → highest energy radiation.
🔎 Among the given options:
📌 Ultraviolet: shorter than visible, but longer than X rays
📌 Infrared: longer than visible
📌 Radiowaves: longest wavelength
📌 X rays: shorter wavelength than UV, IR, and radiowaves
👉 Therefore, X rays have the minimum wavelength among the listed options.

8: The strongest oxidizing agent in the electro chemical series is:

a) Li

b) F

c) H₂

d) Cu

✅ Correct Answer: (b) F
🔎📌 Short Reason
The strongest oxidizing must have highest reduction potential. In ECS, F has the highest reduction potential, therefore fluorine is the strongest oxidizing agent.

9: Galvanized rod of iron is coated with:

a) Nickel

b) Chromium

c) Carbon

d) Zinc

✅ Correct Answer: (d) Zinc
🔎📌 Short Reason
Galvanized iron is coated with zinc. Galvanizing is the type of electroplating involving coating of zinc on baser metals like iron.

10: Oxidation number of Cr in Na₂Cr₂O₇, is:

a) +3

b) +8

c) +6

d) +12

✅ Correct Answer: (c) +6
🔎📌 Short Reason
In Na₂Cr₂O₇ → 2(+1) + 2x + 7(−2) = 0 ⇒ 2x = 12 ⇒ x = +6.
🔎🧠 Step by Step Reasoning
📌 Oxidation number of Na = +1
📌 Oxidation number of O = −2
📌 In a neutral compound, sum of oxidation numbers of all atoms is equal to zero.
2(Na) + 2Cr + 7(O) = 0
2(+1) + 2Cr + 7(−2) = 0
2 + 2Cr + (−14) = 0
2 + 2Cr −14 = 0
2Cr −12 = 0
2Cr = +12
👉 Cr = +12/2 = +6

11: Which of the following half-cell reaction show oxidation?

a) Fe³⁺ → Fe²⁺

b) Cl₂→ 2Cl⁻

c) SO₄²⁻ → SO₃²⁻

d) Zn → Zn²⁺

✅ Correct Answer: (d) Zn → Zn²⁺
🔎📌 Short Reason
Oxidation means increase in oxidation number of atom during a reaction.
The conversion of Zn (ON =0) to ion (ON = +2) involves loss of 2 electrons which is manifested by the 2 units increase in oxidation number.
🔎🧠 Step by Step Reasoning
⚡In reaction (a) where ferric ion (ON = +3) changes into ferrous ion (ON = +2) is reduction as oxidation number of Fe has been decreased.
⚡In reaction (b) where chlorine (ON = 0) changes into chloride ion (ON = −1) is reduction as oxidation number of Cl has been decreased.
⚡In reaction (c) where sulphate ion (ON = +6) changes into sulphite ion (ON = +4) is reduction as oxidation number of S has been decreased.

12: Fuel cell is a typical Galvanic cell which is based on the reaction between:

a) Nitrogen and oxygen

b) Methane and oxygen

c) Hydrogen and oxygen

d) Hydrogen & zinc

✅ Correct Answer: (c) Hydrogen and oxygen
🔎📌 Short Reason
Fuel cells are galvanic cells where H₂ reacts with O₂ to produce electricity and water. In a fuel cell, hydrogen is oxidized at the anode and oxygen is reduced at the cathode, generating continuous current.
🔎🧠 Step by Step Reasoning
⚡Cathode ………… Platinum coated porous graphite
⚡Anode ………….. Platinum coated porous graphite
⚡Electrolyte ……... Concentrated alkaline electrolyte like KOH
⚡Hydrogen gas ….. fed to anode side (where it reacts with four OH⁻ to produce 4 water molecules)
⚡Oxygen gas ……. Fed to the cathode side (where it reacts with water to produced four OH⁻ ions)

13: In Zn-SHE voltaic cell, the half reaction occurs at anode is

a) Zn²⁺ + 2ē → Zn

b) Zn → Zn²⁺ +2ē

c) 2H⁺ + 2ē → H₂

d) H₂ → 2H⁺ + 2ē

✅ Correct Answer: (b) Zn → Zn²⁺ +2ē
🔎📌 Short Reason
In Zn-SHE voltaic cell, zinc oxidizes to zinc ion (Zn²⁺) at anode (while SHE or hydrogen ion reduces to H₂ gas at cathode).

14: This statement is not correct for lead storage battery:

a) It can be recharged

b) It is a primary battery

c) Anode is made up of lead

d) Cathode is made up of lead oxide

✅ Correct Answer: (b) It is a primary battery
🔎📌 Short Reason
The lead storage battery is called a secondary cell because its chemical reactions are reversible — it can be recharged after discharge, unlike a primary cell which is single use .
🔎🧠 Step by Step Reasoning
A primary battery is one that cannot be recharged — it works until its reactants are consumed. The lead storage battery, however, is designed for reversible reactions:
⚡Oxygen gas ……. Fed to the cathode side (where it reacts with water to produced four OH⁻ ions)
⚡During discharge → Pb and PbO₂ react with H₂SO₄ to form PbSO₄.
⚡During recharge → PbSO₄ is converted back to Pb and PbO₂.
👉🏼Because this cycle can repeat, the lead storage battery is a secondary battery, not a primary one.

15: The spectrum of helium atom (He) is expected to be similar to that of:

a) H atom

b) Li atom

c) Na⁺ ion

d) Li⁺ ion

✅ Correct Answer: (d) Li⁺ ion
🔎📌 Short Reason
Spectral lines depend on electronic structure. Neutral helium has 2 electrons. The only option with 2 electrons is Li⁺ (atomic number 3, one electron removed → 2 left). Hence, their spectra are similar.
👉 Therefore, the helium atom (He) spectrum is expected to be similar to Li⁺ ion, because both have two electrons and thus comparable electronic structures.

16: The maximum number of electrons in the outermost orbits is same as that of electrons in the valence shell of

a) He

b) N

c) Al

d) Ne

✅ Correct Answer: (d) Ne
🔎📌 Short Reason
By the octet rule, the outermost orbit or valence shell can hold a maximum of 8 electrons. All noble gases (except He) like Neon (Ne) has exactly 8 electrons in its valence shell, so its configuration matches this maximum.

17: The spectrum of hydrogen atom is similar to that of:

a) H⁺ ion

b) He⁺ ion

c) Li⁺ ion

d) Na⁺ ion

✅ Correct Answer: (b) He⁺ ion
🔎📌 Short Reason
Spectral similarity occurs when two or more species have same number of electrons. The hydrogen atom has one electron. The only option with one electron is He⁺, so its spectrum is similar to hydrogen’s.

18: The effect of electric field on the spectra of atoms is called:

a) Photoelectric effect

b) Stark effect

c) Compton effect

d) Zeeman effect

✅ Correct Answer: (b) Stark effect
🔎📌 Short Reason
Spectral lines of atoms split or shift when subjected to an external electric field. This phenomenon is known as the Stark effect.

19: The energy of hydrogen atom in its ground state is –13.6 eV. The energy of the level corresponding to n = 3 is:

a) –4.53 eV

b) –13.6 eV

c) –2.265 eV

d) –1.51 eV

✅ Correct Answer: (d) –1.51 eV
🔎📌 Short Reason
Energy decreases in magnitude as n increases. For n = 3, the energy is –1.51 eV, which is less negative than the ground state, meaning the electron is less tightly bound
🔎🧠 Step by Step Reasoning
🔎Formula for energy of electron in hydrogen atom:
⚡ Eₙ = E₁/n²
⚡O₂ is more stable allotropic form than O₃ (ozone) and therefore, ΔHf° of O₂ is assumed to be zero.
⚡Rhombic sulphur has ΔHf° = 0 as it is the most stable allotrope of sulphur.
⚡where E₁ = −13.6 eV (ground state energy).
⚡For n = 3:
⚡E₃ = −13.6/3² = −13.6/9 = −1.51 eV✅

20: Eₙ = −1311.8 kJmol⁻¹, If the value of E is −52.44 kJmol⁻¹, to which value ‘n’ corresponds?

a) 5

b) 3

c) 2

d) 4

✅ Correct Answer: (a) 5
🔎📌 Short Reason
The energy of the nth orbit is inversely proportional to n². Solving gives n²= 25, hence n=5.
🔎🧠 Step by Step Reasoning
🔎Formula for energy of electron in hydrogen atom:
⚡ Eₙ = E₁/n²
⚡where E₁ =−1311.8 kJ mol⁻¹.
⚡n² = E₁/Eₙ
⚡Substitute given energy:
⚡n² = −1311.8/−52.44
⚡n² = 25
⚡n = 5 (Take square root) ✅👈

21: The ground state of an atom corresponds to a state of

a) Zero energy

b) Negative energy

c) Minimum energy

d) Maximum energy

✅ Correct Answer: (c) Minimum energy
🔎📌 Short Reason
The ground state is the most stable state of an atom, with the lowest (minimum) energy. The energy is negative, indicating the electron is bound to the nucleus.
👉🏼So the ground state corresponds to minimum energy, not zero or maximum.

22: An atom of calcium (Z = 20) contains ………….. electrons in the third energy level.

a) 18

b) 10 temperature

c) 8

d) 2

✅ Correct Answer: (c) 8
🔎📌 Short Reason
Calcium has 20 electrons. In the third shell (n = 3), only 3s² and 3p⁶ are filled →
👉 8 electrons.

23: The number of electrons in the 4th shell of potassium (Z = 19) is …………..

a) 1

b) 2

c) 8

d) 18

✅ Correct Answer: (a) 1
🔎📌 Short Reason
Potassium has 19 electrons. Electronic configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹. Its outermost shell (n = 4) contains only one electron (4s¹).

24: Out of the following pairs of elements, which has the same number of electrons in the outermost energy level?

a) Lithium and hydrogen

b) Boron and carbon

c) Carbon and nitrogen property

d) Helium and lithium

✅ Correct Answer: (a) Lithium and hydrogen
🔎📌 Short Reason
Elements of same group have same number of valence electrons in the outermost energy level.
👉Lithium (1s² 2s¹) and hydrogen (1s¹) both are present in the same group IA have 1 electron in their outermost shell, so their valence electron count is the same.

25: According to de Broglie’s equation, the momentum of a particle in motion is …….. proportional to wavelength.

a) Inversely

b) Directly

c) Is not

d) None of these

✅ Correct Answer: (a) Inversely
🔎📌 Short Reason
de Broglie proposed that matter has wave nature. The wavelength associated with a particle is inversely proportional to its momentum: λ=h/mv (de Broglie’s equation).

26: The wavelength of large objects is of no significance as it is too ………… to be measurable.

a) Large

b) Heavy

c) Small

d) None of these

✅ Correct Answer: (c) Small
🔎📌 Short Reason
Large objects have enormous mass, so their de Broglie wavelength is extremely small, making it practically insignificant and impossible to measure with current instruments.

27: The colour of light depends upon its:

a) Source

b) Wavelength

c) Velocity

d) None of these

✅ Correct Answer: (b) Wavelength
🔎📌 Short Reason
The colour of light depends on its wavelength (or frequency), not on its source or velocity. Different wavelengths correspond to different colours. The source only emits light of certain wavelengths, but the colour itself is fundamentally tied to wavelength.

28: The oxidation number of Ni in Ni(CO)₄ is:

a) –2

b) 0

c) +2

d) +4

✅ Correct Answer: (b) 0
🔎📌 Short Reason
Ni(CO)₄ is nickel tetracarbonyl, a neutral complex.
In Ni(CO)₄, the CO ligands are neutral → contributes 0 charge, and the complex itself is neutral.
👉🏼Therefore, the oxidation number of Ni is 0.

29: The shape of SO₂ is:

a) Tetrahedral

b) Planar Trigonal

c) Linear

d) Pyramidal

✅ Correct Answer: (b) Planar Trigonal
🔎📌 Short Reason
SO₂ has a bent/angular shape because of one lone pair on sulfur, but the electron geometry is trigonal planar.
👉🏼Hence, the correct option is (b) Planar Trigonal.
🔎🧠 Step by Step Reasoning
🔎SO₂ molecule:
Sulfur (S) is the central atom.
Oxygen atoms form double bonds with sulfur.
🔎Total valence electrons = 6 (S) + 6×2 (O) = 18.
🔎Structure: O=S–O with one lone pair on sulfur.
🔎VSEPR theory:
Central atom (S) has 3 regions of electron density (two bonding pairs + one lone pair).
This corresponds to AX₂E type.
🔎Geometry: trigonal planar electron geometry, but due to lone pair → bent (angular) molecular
shape. 👉🏼So, SO₂ is planar and bent, often described as planar trigonal or distorted planar trigonal. ✅ 👈

30: The rate of diffusion of H₂ and D₂ is:

a) 1.41:1

b) 3:1

c) 2:1

d) 1.5:1

✅ Correct Answer: (a) 1.41:1
🔎📌 Short Reason
According to Graham’s law, lighter gases diffuse faster (Rate of diffusion ∝ 1/√M).
Since H₂ (2 g/mol) is lighter than D₂ (4 g/mol), the diffusion rate ratio is √2 ≈ 1.41 : 1 👈 .
🔎🧠 Step by Step Reasoning
🔎 Graham’s law: Rate of diffusion ∝ 1/√M
where M = molar mass.
🔎 Molar masses:
H₂ = 2 g/mol
D₂ = 4 g/mol
🔎 Ratio of rates (H₂ : D₂):
👉🏼rʜ₂/rᴆ₂ = Mᴆ₂/Mʜ₂ = √4/√2 = √2 ≈ 1.41✅

31: The acid dissociation constants of various acids are as:
A 4.8×10⁻¹⁰
B 1.8×10⁻⁴
C 1.8×10⁻⁵
D 1.4×10⁻³
Which is correct order of strength of acids?

a) A > B > C > D

b) D > C > B > A

c) A > B = C > D

d) D > B > C > A

✅ Correct Answer: (d) D > B > C > A
🔎📌 Short Reason
Acid strength increases with higher Kₐ.
Since Kₐ(D)> Kₐ(B)> Kₐ(C)> Kₐ(A),
👉 the correct order is D > B > C > A.
🔎🧠 Step by Step Reasoning
🔎 Rule: Larger Kₐ → stronger acid.
🔎Compare values:
(a) 4.8×10⁻¹⁰ → smallest Kₐ → very weak acid
(b) 1.8×10⁻⁴ → second largest Kₐ
(c) 1.8×10⁻⁵ → third largest Kₐ
(d) 1.4×10⁻³ → Largest Kₐ → strongest
👉 Order (strongest → weakest): D > B > C > A✅
.

32: Glycerin acts as a negative catalyst for the decomposition of:

a) H₂SO₄

b) H₂O

c) NO₂

d) H₂O₂

✅ Correct Answer: (d) H₂O₂
🔎📌 Short Reason
A negative catalyst (inhibitor) slows down the rate of a reaction.
👉 Glycerin is used as a negative catalyst (inhibitor) to prevent the rapid decomposition of hydrogen peroxide (H₂O₂), thereby stabilizing it during storage.

33: Kₛₚ of CdS is 3.6×10⁻²⁹ mol²·dm⁻⁶. If the ionic product is 1.4×10⁻²⁵ mol²·dm⁻⁶:

a) ppt will form

b) ppt will not form

c) ppt disappear

d) None of them

✅ Correct Answer: (a) ppt will form
🔎📌 Short Reason
Because the ionic product (1.4 × 10⁻²⁵) is much greater than the Kₛₚ (3.6 × 10⁻²⁹) of CdS, the solution is supersaturated and a precipitate of CdS will form.
🔎🧠 Step by Step Reasoning
🔎Rule:
⚡If Ionic Product (IP or Qₛₚ) < Kₛₚ → solution is unsaturated → no ppt forms.
⚡If IP or Qₛₚ = Kₛₚ → solution is saturated → equilibrium, no ppt.
⚡If IP or Qₛₚ > Kₛₚ → solution is supersaturated → ppt forms.
🔎Given:
Kₛₚ = 3.6×10⁻²⁹
IP = 1.4×10⁻²⁵
🔎Compare:
IP≫Kₛₚ
👉 Since IP > Kₛₚ, the solution is supersaturated → precipitate will form. ✅

34: The total number of ions in CaCl₂ is:

a) 24.08 × 10²³

b) 18.06 × 10²³

c) 12.04 × 10²³

d) 6.02 × 10²³

✅ Correct Answer: (b) 18.06 × 10²³
🔎📌 Short Reasoning
One mole of CaCl₂ dissociates into 3 ions per formula unit. Multiplying by Avogadro’s number gives a total of 18.06 × 10²³ ions 👈

35: The sample of caffeine weighs 0.02060 g. The significant figures in the sample is:

a) 3

b) 4

c) 5

d) 6

✅ Correct Answer: (b) 3.01 × 10²⁴
🔎📌 Short Reason
The value 0.02060 g has 4 significant figures (2, 0, 6, 0). Leading zeros are not counted, but captive zeros and trailing zeros after the decimal are.

36: The ionization of NH₄OH is suppressed by adding:

a) HCl

b) NH₄Cl

c) (NH₂)₂CO

d) H₂S

✅ Correct Answer: (b) NH₄Cl
🔎📌 Short Reason
The ionization of NH₄OH (a weak base or weak electrolyte) is suppressed by adding NH₄Cl (strong electrolyte) due to the common ion effect (extra NH₄⁺ ions shift equilibrium backward, reducing ionization).

37: The octet rule is NOT valid for this molecule:

a) H₂

b) BF₃

c) NO

d) All of these

✅ Correct Answer: (d) All of these
🔎📌 Short Reason
The octet rule is not valid for H₂ (duplet), BF₃ (incomplete octet), and NO (odd electron molecule).
👉 Hence, the correct option is (d) All of these.

38: Rate = K [NH₃]². Keeping the other conditions same, if the concentration of NH₃ is doubled, then the initial rate of reaction will be:

a) 2X

b) 8X

c) 16X

d) 4X

✅ Correct Answer: d) 4X
🔎📌 Short Reason
The reaction is second order in NH₃, Rate ∝ [NH₃]² → doubling [NH₃] makes rate 2² = 4 times, i.e. 4X.
🔎🧠 Step by Step Reasoning
🔎The rate law is:
Rate = K[NH₃]²
Reaction order with respect to NH₃ = 2 (second order).
If concentration of NH₃ is doubled:
🔎New Rate=K(2[NH₃])² = K⋅4[NH₃]²
👉 That means the rate becomes 4 times the original rate. ✅

39: de-Broglie’s equation is

a) λ = mv/h

b) λ = hmv

c) λ = h/mv

d) λ = hv/v

✅ Correct Answer: c) λ = h/mv
🔎📌 Short Reason
de Broglie showed that matter has wave nature. The wavelength of a particle is given by: λ = h/mv
where h = Planck’s constant, m = mass, and v = velocity..

40: The value of azimuthal quantum number for last electron of N-atom is?

a) 3

b) 2

c) 1

d) 0

✅ Correct Answer: (c) 1
🔎📌 Short Reason
Nitrogen (Z = 7) → electronic configuration: 1s² 2s² 2p³. The last electron enters the 2p orbital. For a p-orbital, the azimuthal quantum number l=1.
👉 Hence, the value of l for the last electron of N atom is 1.

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کیوں پسینہ میں شرابور ہوئی جاتی ہو 💦

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

بات ہی کب کسی کی مانی ہے 🤷‍♀️
اپنی ہٹ پوری کر کے چھوڑو گی 😏
یہ کلائی یہ جسم اور یہ کمر 💃
تم صراحی ضرور توڑو گی 🏺

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

تم ہو جاناں شباب و حسن کی آگ 🔥
آگ کی طرح اپنی آنچ میں گم 🌹
پھر مرے بازوؤں پہ جھک آئیں 🤲
لو اب مجھے جلا ہی ڈالو تم 💔

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

آپ کی تلخ نوائی کی ضرورت ہی نہیں 😶
میں تو ہر وقت ہی مایوسِ کرم رہتا ہوں 💭
آپ سے مجھ کو ہے اک نسبتِ احساسِ لطیف 🌸
لوگ کہتے ہیں ، مگر میں تو نہیں کہتا ہوں 🤐

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

چڑھ گیا سانس جھک گئیں نطریں 😮‍💨
رنگ رخسار میں سمٹ آیا 🌹
زکر سن کر مری محبت کا 💕
اتنے بیٹھے تھے ، کون شرمایا ؟ 😊

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

تم زمانے سے لڑ نہیں سکتیں ⚔️
خیر یہ راز آج کھول دیا 🔓
وہ اجازت کہ جا رہو ہوں میں 🚶‍♀️
تم نے باتوں میں زہر کھول دیا ☠️

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

دور نظروں سے خلوتِ دل میں 👁️
اس طرح آج اُن کی یاد آئی 💭
ایک بستی کے پار شام کا وقت 🌆
جیسے بجتی ہو شہنائی 🎶

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

ہیں بے طور یہ لوگ تمام 😒
ان کے سانچہ میں نہ ڈھلو 🧱
میں بھی یہاں سے بھاگ چلوں 🏃‍♂️
تم بھی یہاں سے بھاگ چلو 🏃‍♀️

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

عشق سمجھے تھے جس کو وہ شاید 💕
تھا بس اک نارسائی کا رشتہ 😔
میرے اور اُس کے درمیاں نکلا 💔
عمر بھر کی جدائی کا رشتہ 🕰️

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

ہے یہ بازار جھوٹ کا بازار 🛍️
پھر یہی جنس کیوں نہ تولیں ہم ⚖️
کر کے اک دوسرے سے عہدِ وفا 🤝
آؤ کچھ دیر جھوٹ بولیں ہم 🎭

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

کون سود و زیاں کی دنیا میں 💰
دردِ غربت کا ساتھ دیتا ہے 😢
جب مقابل ہوں عشق اور دولت ⚖️
حُسن دولت کا ساتھ دیتا ہے 👑

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

یہ تیرے خط تیری خوشبو یہ تیری خواب و خیال ✉️🌸
متاعِ جاں ہیں ترے قول و قسم کی طرح 💎
گزشتہ سال انہیں میں نے گِن کے رکھا تھا 📜
کسی غریب کی جوڑی ہوئی رقم کی طرح 💵

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

ہر بار تجھ سے ملتے وقت 🌹
تجھ سے ملنے کی آرزو کی ہے 💭
تیرے جانے کے بعد بھی میں نے 💔
تیری خوشبو سے گفتگو کی ہے 🌸

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

سال ہا سال اور اِک لمحہ 🕰️
کوئی بھی تو نہ اِن میں بل آیا 😔
خود ہی اِک در پہ میں نے دستک دی 🚪
خود ہی لڑکا سا میں نکل آیا 🙂

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

میری عقل و ہوش کی سب حالتیں 🧠
تم نے سانچے میں جنوں کے ڈھال دیں 🔥
کر لیا تھا میں نے عہدِ ترکِ عشق 💔
تم نے پھر بانہیں گلے میں ڈال دیں 🤲

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

تم جب آؤ گی کھویا ہوا پاؤ گی مجھے 🌌
میری تنہائی میں خوابوں کے سوا کچھ بھی نہیں 💭
میرے کمرے کو سجانے کی تمنا ہے تمہیں 🏠
میرے کمرے میں کتابوں کے سوا کچھ بھی نہیں 📚

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

جو رعنائی نگاہوں کے لئے فردوسِ جلوہ ہے 👀✨
لباس مفلسی میں کتنی بے قیمت نظر آتی 👗
یہاں تو جاذبیت بھی ہے دولت ہی کی پروردہ 💰
یہ لڑکی فاقہ کش ہوتی تو بدصورت نظر آتی 😔

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

شرم ، دہشت ، جھجک ، پریشانی 😳
ناز سے کام کیوں نہیں لیتیں 🌸
آپ،وہ،جی،مگر ’’یہ سب کیا ہے‘‘ 🤔
تم مرا نام کیوں نہیں لیتیں ❓

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

عجب تھا اس کی دلداری کا انداز 💕
وہ برسوں بعد جب مجھ سے مِلا ہے 🤝
بَھلا میں پوچھتا اس سے تو کیسے 🤔
متاعِ جاں! تمہارا نام کیا ہے 💖

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

تیری یادوں کے راستے کی طرف 🌌
اک قدم بھی نہیں بڑھوں گا میں 🚶‍♂️
دل تڑپتا ہے تیرے خط پڑھ کر 💌
اب ترے خط نہیں پڑھوں گا میں ❌

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

لہو روتے نہ اگر ہم دمِ رخصت یاراں 💔
کیا عجب تھا کہ کوئی اور تماشہ کرتے 🎭
چلو اچھا ہے کہ وہ بھی نہیں نزدیک اپنے 🚶‍♂️
وہ جو ہوتا تو اُسے بھی نہ گوارا کرتے 😔

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

اب میں سمجھا ہوں بیکسی کیا ہے 😞
اب تمہیں بھی مرا خیال نہیں 💭
ہائے ! یہ عشق کا زوال کہ اب 💔
ہجر میں ہجر کا ملال نہیں 🌌

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

دل میں جن کا نشان بھی نہ رہا 💭
کیوں نہ چہروں پہ اب وہ رنگ کھلیں 🎨
اب تو خالی ہے روح جذبوں سے 😔
اب بھی کیا ہم تپاک سے نہ ملیں 🤝

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

ہے ضرورت بہت توجہ کی 🌟
یاد آؤ تو کم نہ یاد آؤ 💭
چاہئے مجھ کو جان و دل کا سکوں 🕊️
میرے حق میں عذاب بن جاؤ ⚡

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

کوئی تعلق ہی نہ رہے 🔗
جب کہ سبب بھی باقی ہو ❓
کیا میں اب بھی زندہ ہوں 🕰️
کیا تم اب بھی باقی ہو? 💔

🌟 یہ انتخاب آپ کے لئے پیش ہے 🌟
جون ایلیا کے قطعات ہمیشہ دل کو چھو لیتے ہیں۔
انام جذبی کی جانب سے یہ پوسٹ آپ سب کی نذر ہے ✨📖

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

تیری یادوں کے راستے کی طرف 🌌
اک قدم بھی نہیں بڑھوں گا میں 🚶‍♂️
دل تڑپتا ہے تیرے خط پڑھ کر 💌
اب ترے خط نہیں پڑھوں گا میں ❌

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

بات ہی کب کسی کی مانی ہے 🤷‍♀️
اپنی ہٹ پوری کر کے چھوڑو گی 😏
یہ کلائی یہ جسم اور یہ کمر 💃
تم صراحی ضرور توڑو گی 🏺

🔥⚙️ جون ایلیا ۔ قطعہ 🔥⚙️

مر چکا ہے دل مگر زندہ ہوں میں 💔
زہر جیسی کچھ دوائیں چاہییں 💊
پوچھتی ہیں آپ، آپ اچھے تو ہیں 🙂
جی میں اچھا ہوں، دعائیں چاہییں 🙏

✨ اگر آپ کو یہ کلام پسند آیا ✨
تو بلاگ کو سبسکرائب کریں 📩
اور اپنی رائے سے آگاہ کریں 💬
محبت کے اس سفر میں ساتھ رہیں ❤️
— انعام جذبی