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MDCAT/ECAT Quiz # 1 (Group Trend of Representative Elements): InamJazbi Learn Chemistry 🚀
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1. Melting and boiling points of which of the following group of representative elements decrease regularly down the group?
Explanation: Metallic bonds weaken as atomic size increases, so melting & boiling points decrease down the group.
- ☐ a) Group IA
- ☐ b) Group IIIA
- ☐ c) Group VIIA
- ☐ d) Group VIIIA
Show Answer & Explanation
✅ Answer: a) Group IAExplanation: Metallic bonds weaken as atomic size increases, so melting & boiling points decrease down the group.
2. Which of the following s-block elements forms superoxide when burned in air?
Explanation: Superoxides contain O₂⁻. Larger alkali metals like K, Rb, Cs form superoxides because their large cations stabilize the O₂⁻ ion. Li forms normal oxide, Na forms peroxide, Mg forms normal oxide.
- ☐ a) Li
- ☐ b) Na
- ☐ c) K
- ☐ d) Mg
Show Answer & Explanation
✅ Answer: c) KExplanation: Superoxides contain O₂⁻. Larger alkali metals like K, Rb, Cs form superoxides because their large cations stabilize the O₂⁻ ion. Li forms normal oxide, Na forms peroxide, Mg forms normal oxide.
3. Which of the following formula of nitrides for alkaline earth metal is possible?
Explanation: Alkaline earth metals have +2 charge (M²⁺), nitride ion is N³⁻. LCM of 2 and 3 = 6 → formula = M3N2.
- ☐ a) MN₃
- ☐ b) M₂N₃
- ☐ c) M₃N
- ☐ d) M₃N₂
Show Answer & Explanation
✅ Answer: d) M3N2Explanation: Alkaline earth metals have +2 charge (M²⁺), nitride ion is N³⁻. LCM of 2 and 3 = 6 → formula = M3N2.
4. The flame colour of which of the following alkali metals is yellow?
Explanation: Flame test colors: Li → crimson red, Na → bright yellow, K → lilac, Rb → red-violet, Cs → blue-violet.
- ☐ a) Na
- ☐ b) K
- ☐ c) Rb
- ☐ d) Cs
Show Answer & Explanation
✅ Answer: a) NaExplanation: Flame test colors: Li → crimson red, Na → bright yellow, K → lilac, Rb → red-violet, Cs → blue-violet.
5. The chemical used in fireworks is:
Explanation: KNO₃ is a strong oxidizer needed for rapid combustion and colorful explosions. Others are not suitable.
- ☐ a) Bleaching powder
- ☐ b) Sodium bicarbonate
- ☐ c) Potassium nitrate
- ☐ d) Potash alum
Show Answer & Explanation
✅ Answer: c) Potassium nitrateExplanation: KNO₃ is a strong oxidizer needed for rapid combustion and colorful explosions. Others are not suitable.
6. Cathode in Castner Kellner cell is:
Explanation: Cathode is mercury (Hg), anode is titanium.
- ☐ a) Titanium blocks
- ☐ b) Carbon rods
- ☐ c) Mercury
- ☐ d) Iron container
Show Answer & Explanation
✅ Answer: c) MercuryExplanation: Cathode is mercury (Hg), anode is titanium.
7. The diagonal member of beryllium is:
Explanation: Be and Al have a diagonal relationship due to similar charge/radius ratio and electronegativity.
- ☐ a) Mg
- ☐ b) Al
- ☐ c) Si
- ☐ d) C
Show Answer & Explanation
✅ Answer: b) AlExplanation: Be and Al have a diagonal relationship due to similar charge/radius ratio and electronegativity.
8. Purification of SO₂ from arsenic oxide is essential in the contact process to avoid:
Explanation: Arsenic oxide poisons the V₂O₅ catalyst in the SO₂ → SO₃ reaction, reducing efficiency.
- ☐ a) Catalyst poisoning
- ☐ b) Temperature elevation
- ☐ c) Pressure controlling
- ☐ d) Air mixing
Show Answer & Explanation
✅ Answer: a) Catalyst poisoningExplanation: Arsenic oxide poisons the V₂O₅ catalyst in the SO₂ → SO₃ reaction, reducing efficiency.
9. Oil of vitriol refers to:
Explanation: “Oil of vitriol” is the old alchemical name for H₂SO₄ due to its oily appearance.
- ☐ a) Borax
- ☐ b) Sulphuric Acid
- ☐ c) Alum
- ☐ d) Caustic soda
Show Answer & Explanation
✅ Answer: b) Sulphuric AcidExplanation: “Oil of vitriol” is the old alchemical name for H₂SO₄ due to its oily appearance.
10. The best oxidizing agent among halogens is:
Explanation: Fluorine has the highest reduction potential (+2.87 V) and electronegativity, making it the strongest oxidizer among halogens. Oxidizing power decreases down the group: F₂ > Cl₂ > Br₂ > I₂.
- ☐ a) F₂
- ☐ b) Cl₂
- ☐ c) Br₂
- ☐ d) I₂
Show Answer & Explanation
✅ Answer: a) F₂Explanation: Fluorine has the highest reduction potential (+2.87 V) and electronegativity, making it the strongest oxidizer among halogens. Oxidizing power decreases down the group: F₂ > Cl₂ > Br₂ > I₂.
11. The electronic configuration of s-block metal, M is 1s² 2s² 2p⁶ 3s¹. The formula of its oxide would be:
Explanation: M has configuration 1s² 2s² 2p⁶ 3s¹ → Group IA (Na). Oxidation state = +1, O²⁻. Balance charges: 2M⁺ + O²⁻ → M₂O.
- ☐ a) MO
- ☐ b) M₂O
- ☐ c) M₂O₂
- ☐ d) MO₂
Show Answer & Explanation
✅ Answer: b) M₂OExplanation: M has configuration 1s² 2s² 2p⁶ 3s¹ → Group IA (Na). Oxidation state = +1, O²⁻. Balance charges: 2M⁺ + O²⁻ → M₂O.
12. The element lithium bears resemblance with:
Explanation: Lithium (Li) shows diagonal relationship with Mg: similar ionic sizes, charge/radius ratio. Both form nitrides (Li₃N, Mg₃N₂), sparingly soluble salts, and show covalent character in many compounds.
- ☐ a) Al
- ☐ b) Mg
- ☐ c) Si
- ☐ d) None of them
Show Answer & Explanation
✅ Answer: b) MgExplanation: Lithium (Li) shows diagonal relationship with Mg: similar ionic sizes, charge/radius ratio. Both form nitrides (Li₃N, Mg₃N₂), sparingly soluble salts, and show covalent character in many compounds.
13. The electronic configuration of a metal, M is 1s² 2s². The diagonal member of this element has electronic configuration:
Explanation: M = Be (1s² 2s²). Diagonal relationship: Be ↔ Al. Al configuration = 1s² 2s² 2p⁶ 3s² 3p¹.
- ☐ a) 1s² 2s¹
- ☐ b) 1s² 2s² 2p⁶ 3s¹
- ☐ c) 1s² 2s² 2p⁶ 3s² 3p¹
- ☐ d) 1s²
Show Answer & Explanation
✅ Answer: c) 1s² 2s² 2p⁶ 3s² 3p¹Explanation: M = Be (1s² 2s²). Diagonal relationship: Be ↔ Al. Al configuration = 1s² 2s² 2p⁶ 3s² 3p¹.
14. Which of the following s-block elements only forms normal oxide when burned in air?
Explanation: Li → Li₂O, Be → BeO, Mg → MgO. All form only normal oxides.
- ☐ a) Li
- ☐ b) Be
- ☐ c) Mg
- ☐ d) All of them
Show Answer & Explanation
✅ Answer: d) All of themExplanation: Li → Li₂O, Be → BeO, Mg → MgO. All form only normal oxides.
15. Which of the following alkali metals only forms normal oxide when burned in air?
Explanation: Only Li forms normal oxide (Li₂O). Na forms peroxide, K/Rb/Cs form superoxides.
- ☐ a) Li
- ☐ b) Be
- ☐ c) Ca
- ☐ d) Na
Show Answer & Explanation
✅ Answer: a) LiExplanation: Only Li forms normal oxide (Li₂O). Na forms peroxide, K/Rb/Cs form superoxides.
16. Which of the following formula of nitrides for alkali metal is possible?
Explanation: Alkali metals = +1, N³⁻ → 3M⁺ + N³⁻ → M₃N. Only lithium forms stable nitride (Li₃N) at room temperature.
- ☐ a) MN₃
- ☐ b) M₂N₃
- ☐ c) M₃N
- ☐ d) MN
Show Answer & Explanation
✅ Answer: c) M₃NExplanation: Alkali metals = +1, N³⁻ → 3M⁺ + N³⁻ → M₃N. Only lithium forms stable nitride (Li₃N) at room temperature.
17. Which of the following formula of nitrides for Group IIIA is possible?
Explanation: Group IIIA = +3, N³⁻ → charges balanced 1:1 → MN.
- ☐ a) MN₃
- ☐ b) M₂N₃
- ☐ c) M₃N
- ☐ d) MN
Show Answer & Explanation
✅ Answer: d) MNExplanation: Group IIIA = +3, N³⁻ → charges balanced 1:1 → MN.
18. Which group elements form nitrides with general formula M₃N₄?
Explanation: Group IVA = +4, N³⁻ → 3(M⁴⁺) + 4(N³⁻) → M₃N₄.
- ☐ a) IIIA
- ☐ b) IIA
- ☐ c) VA
- ☐ d) IVA
Show Answer & Explanation
✅ Answer: d) IVAExplanation: Group IVA = +4, N³⁻ → 3(M⁴⁺) + 4(N³⁻) → M₃N₄.
19. Which group elements form nitrides with general formula M₃N₅?
Explanation: Group VA = +5, N³⁻ → 3(M⁵⁺) + 5(N³⁻) → M₃N₅.
- ☐ a) IIIA
- ☐ b) IVA
- ☐ c) VA
- ☐ d) IIA
Show Answer & Explanation
✅ Answer: c) VAExplanation: Group VA = +5, N³⁻ → 3(M⁵⁺) + 5(N³⁻) → M₃N₅.
20. Which group elements form superoxides with general formula MO₂?
Explanation: Larger alkali metals (K, Rb, Cs) stabilize O₂²⁻ → form MO₂ superoxides.
- ☐ a) IA
- ☐ b) IVA
- ☐ c) IIIA
- ☐ d) IIA
Show Answer & Explanation
✅ Answer: a) IAExplanation: Larger alkali metals (K, Rb, Cs) stabilize O₂²⁻ → form MO₂ superoxides.
21. Which of the following gas is evolved when phosphorus reacts with water?
Explanation: White phosphorus reacts with hot concentrated alkali or under special conditions to produce phosphine (PH₃). This is an auto-redox reaction: P oxidized to phosphoric acid (P⁵⁺) and reduced to PH₃ (P³⁻). With pure water the reaction is negligible.
- ☐ a) NH₃
- ☐ b) PH₃
- ☐ c) H₂
- ☐ d) H₂S
Show Answer & Explanation
✅ Answer: b) PH₃Explanation: White phosphorus reacts with hot concentrated alkali or under special conditions to produce phosphine (PH₃). This is an auto-redox reaction: P oxidized to phosphoric acid (P⁵⁺) and reduced to PH₃ (P³⁻). With pure water the reaction is negligible.
22. The general formula of alkali metal alkoxide is:
Explanation: Alkali metals (M⁺) react with alkoxide ion (RO⁻, e.g., C₂H₅O⁻) → M⁺ + RO⁻ → C₂H₅OM.
- ☐ a) C₂H₅OM
- ☐ b) C₂H₅COONa
- ☐ c) (C₂H₅)₂M
- ☐ d) None of them
Show Answer & Explanation
✅ Answer: a) C₂H₅OMExplanation: Alkali metals (M⁺) react with alkoxide ion (RO⁻, e.g., C₂H₅O⁻) → M⁺ + RO⁻ → C₂H₅OM.
23. The chemical formula of lithium ethoxide is:
Explanation: Lithium ion (Li⁺) reacts with ethoxide (C₂H₅O⁻) → C₂H₅OLi or LiOC₂H₅.
- ☐ a) (C₂H₅)₂Li
- ☐ b) C₂H₅COOLi
- ☐ c) C₂H₅OLi
- ☐ d) None of them
Show Answer & Explanation
✅ Answer: c) C₂H₅OLiExplanation: Lithium ion (Li⁺) reacts with ethoxide (C₂H₅O⁻) → C₂H₅OLi or LiOC₂H₅.
24. Alkali metals react with alcohols liberating hydrogen gas along with:
Explanation: 2M + 2C₂H₅OH → 2C₂H₅OM + H₂↑ [M = Li, Na, K]. Alkali metals displace hydrogen from alcohol, forming alkoxide salts and H₂ gas.
- ☐ a) Alkoxide
- ☐ b) Phenoxide
- ☐ c) Carboxylate
- ☐ d) None of them
Show Answer & Explanation
✅ Answer: a) AlkoxideExplanation: 2M + 2C₂H₅OH → 2C₂H₅OM + H₂↑ [M = Li, Na, K]. Alkali metals displace hydrogen from alcohol, forming alkoxide salts and H₂ gas.
25. The Group IA elements react violently with water making the solution:
Explanation: 2M + 2H₂O → 2MOH + H₂↑. Alkali metal hydroxides (MOH) are strong bases → solution becomes alkaline.
- ☐ a) Acidic
- ☐ b) Neutral
- ☐ c) Alkaline
- ☐ d) Amphoteric
Show Answer & Explanation
✅ Answer: c) AlkalineExplanation: 2M + 2H₂O → 2MOH + H₂↑. Alkali metal hydroxides (MOH) are strong bases → solution becomes alkaline.
26. Which of the following alkali metals imparts lilac colour to the flame?
Explanation: Flame test colors: Li → crimson red, Na → bright yellow, K → lilac, Rb → red-violet, Cs → blue-violet.
- ☐ a) K
- ☐ b) Li
- ☐ c) Cs
- ☐ d) Na
Show Answer & Explanation
✅ Answer: a) KExplanation: Flame test colors: Li → crimson red, Na → bright yellow, K → lilac, Rb → red-violet, Cs → blue-violet.
27. Which of the following metals floats over water?
Explanation: Density < 1 g/cm³ → floats. Na = 0.97 g/cm³, Li = 0.53 g/cm³, K = 0.86 g/cm³ → float; Cs, Rb, Be → sink.
- ☐ a) Cs
- ☐ b) Na
- ☐ c) Rb
- ☐ d) Be
Show Answer & Explanation
✅ Answer: b) NaExplanation: Density < 1 g/cm³ → floats. Na = 0.97 g/cm³, Li = 0.53 g/cm³, K = 0.86 g/cm³ → float; Cs, Rb, Be → sink.
28. The basic strength of alkaline earth metals oxides in water _____ from Be to Ba.
Explanation: MO + H₂O → M(OH)₂. Solubility and ionic character increase down the group → basic strength ↑ (Be → Ba).
- ☐ a) Decreases
- ☐ b) Increases
- ☐ c) Remains same
- ☐ d) Not predictable
Show Answer & Explanation
✅ Answer: b) IncreasesExplanation: MO + H₂O → M(OH)₂. Solubility and ionic character increase down the group → basic strength ↑ (Be → Ba).
29. The element cesium bears resemblance with:
Explanation: Cs is an alkali metal in Group I; no diagonal relationship exists with Cr or Ca → does not resemble.
- ☐ a) Cr
- ☐ b) Ca
- ☐ c) Both a and b
- ☐ d) None of them
Show Answer & Explanation
✅ Answer: d) None of themExplanation: Cs is an alkali metal in Group I; no diagonal relationship exists with Cr or Ca → does not resemble.
30. Which of the following sulphates is NOT soluble in water?
Explanation: Most sulfates soluble except Ba²⁺, Pb²⁺, Sr²⁺, Ca²⁺ (slightly). BaSO₄ → insoluble; others soluble.
- ☐ a) BaSO₄
- ☐ b) ZnSO₄
- ☐ c) K₂SO₄
- ☐ d) Na₂SO₄
Show Answer & Explanation
✅ Answer: a) BaSO₄Explanation: Most sulfates soluble except Ba²⁺, Pb²⁺, Sr²⁺, Ca²⁺ (slightly). BaSO₄ → insoluble; others soluble.
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